IBRAHIM A. answered • 03/30/14

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the first number is x

the other is 3 more than twice the number = 3 + 2*x = 3 +2x

their sum is 57

x + (3 +2x) = 57

x + 2x + 3 = 57 [collecting the like terms]

3x + 3 =57

3x = 57 - 3 [ substract 3 from both sides]

3x =54

3x/3 =54/3 [ divide both sides by 3]

x = 18

The first number is 18

the other number is 3 + 2x [ and x = 18]

so we have 3 + 2 (18) = 3 +36 = 39

The first number is 18 and the other number is 39

add them together to get 57